refactor(utils):改进对于月份差值的计算。
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@ -1,6 +1,8 @@
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package utils
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package utils
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import "time"
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import (
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"time"
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)
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func VeryBeginOfDate(date time.Time) time.Time {
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func VeryBeginOfDate(date time.Time) time.Time {
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return time.Date(date.Year(), date.Month(), date.Day(), 0, 0, 0, 0, date.Location())
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return time.Date(date.Year(), date.Month(), date.Day(), 0, 0, 0, 0, date.Location())
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@ -10,7 +12,7 @@ func VeryEndOfDate(date time.Time) time.Time {
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return time.Date(date.Year(), date.Month(), date.Day(), 23, 59, 59, 999999999, date.Location())
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return time.Date(date.Year(), date.Month(), date.Day(), 23, 59, 59, 999999999, date.Location())
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}
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}
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func IsNextMonth(t1, t2 time.Time) bool {
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func DifferenceInMonth(t1, t2 time.Time) int {
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var differYear, differMonth int
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var differYear, differMonth int
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if t1.After(t2) {
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if t1.After(t2) {
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differYear = t1.Year() - t2.Year()
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differYear = t1.Year() - t2.Year()
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@ -19,5 +21,9 @@ func IsNextMonth(t1, t2 time.Time) bool {
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differYear = t2.Year() - t1.Year()
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differYear = t2.Year() - t1.Year()
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differMonth = int(t2.Month() - t1.Month())
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differMonth = int(t2.Month() - t1.Month())
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}
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}
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return (differMonth == -11 && differYear == 1) || (differMonth == 1 && differYear == 0)
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return differYear*12 + differMonth
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}
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func IsNextMonth(t1, t2 time.Time) bool {
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return DifferenceInMonth(t1, t2) == 1
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}
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}
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